|:B,2 DB, C2 AC|B,D GB AD FA|Gg fe d^c =cA|Fd (3d^cd ed cd|
BG DB, C2 AC|B,D GB AD FA|Gg fe d^c =cF|1 AG GF G4:|2 AG GF G2 (3def||
gd Bd eg fe|de fd ed ^cd|BG DB, C2 AC|B,D GB AD FA|
Gg fe d^c =cA|Fd (3d^cd ed cd|BG DB, C2 AC|1 B,D FA G2 (3def:|2 B,D FA G4||